tolong dibantu kak buat
a.
[tex] \frac{4}{ \sqrt{5} + \sqrt{3} } = \frac{4}{ \sqrt{5} + \sqrt{3} } \times \frac{ \sqrt{5 } - \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \\ = \frac{4( \sqrt{5} - \sqrt{3} ) }{( \sqrt{5} + \sqrt{3}) ( \sqrt{5} - \sqrt{3} )} \\ = \frac{4( \sqrt{5} - \sqrt{3} ) }{5 - 3} \\ = \frac{4( \sqrt{5} - \sqrt{3}) }{2} \\ = 2( \sqrt{5} - \sqrt{3} ) \\ = 2 \sqrt{5} - 2 \sqrt{3} [/tex]
b.
[tex] \frac{2 \sqrt{3} }{2 - \sqrt{3} } = \frac{2 \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } = \frac{2 \sqrt{3} (2 + \sqrt{3)} }{4 - 3} \\ = 2 \sqrt{3} (2 + \sqrt{3} ) \\ = 4 \sqrt{ 3} + 6[/tex]
Semoga membantu, maaf kalau salah
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